-16t^2+134t+62=266

Solution for -16t^2+134t+62=266 equation:

-16t^2+134t+62=266

We move all terms to the left:

-16t^2+134t+62-(266)=0

We add all the numbers together, and all the variables

-16t^2+134t-204=0

a = -16; b = 134; c = -204;
Δ = b2-4ac
Δ = 1342-4·(-16)·(-204)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(134)-70}{2*-16}=\frac{-204}{-32}
=6+3/8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(134)+70}{2*-16}=\frac{-64}{-32}
=+2
$